#include<stdio.h>
int main(int argc, char const *argv[])
{
    int i;
    for(i=0;;i++)
        if(((i*8+7)*8+1)*8+1==(34*i+15)*17+4)
        {
            printf("The required number is:%d\n",(34*i+15)*17+4);
            break;
        }
    return 0;
}
